(x^2)+(1.8*10^-5)x-(3.78*10^-8)=0

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Solution for (x^2)+(1.8*10^-5)x-(3.78*10^-8)=0 equation:



(x^2)+(1.8*10^-5)x-(3.78*10^-8)=0
We add all the numbers together, and all the variables
x^2+(1.8*10^-5)x-8-3.78E=0
We multiply parentheses
x^2+18x^2-5x-8-3.78E=0
We add all the numbers together, and all the variables
19x^2-5x-18.2751053116=0
a = 19; b = -5; c = -18.2751053116;
Δ = b2-4ac
Δ = -52-4·19·(-18.2751053116)
Δ = 1413.90800368
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{1413.90800368}}{2*19}=\frac{5-\sqrt{1413.90800368}}{38} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{1413.90800368}}{2*19}=\frac{5+\sqrt{1413.90800368}}{38} $

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